## Friday, 12 August 2011

### UGC NET SOLVED COMPUTER SCIENCE - PAPER II

This section is for all those NET exam aspirants who are looking out for a solution for UGC NET computer science papers. As a person who had taken the examination i have searched the internet incessantly for the solution of paper-II and paper-III of computer science. Since i could not find any solid help(or rather no help at all) in this regard, i had decided to write my own blog posting the solution for each and every paper as and when i complete it. I have posted the solution for paper-II of December 2008(and it was quite a task). Wherever i could, i have given explanation for the answers. If it is too lengthy or too simple, i have left it out. Enjoy your preparation for the NET exam.

I just have one word of advice for all NET aspirants...

"Focus on the journey, not the destination. Joy is found not in finishing an activity but in doing it.”

# DECEMBER 2008 PAPER II SOLVED

1. The channel capacity of a band-limited Gaussian channel is given by
(A). B log2 (2+S/N) (B) B log2 (1+S/N)
(C ).B log10(1+S/N) (D). B loge(1+S/N)
Ans : B. Explanation :- C=B log2 (1 + S/N) where C is the capacity in bits per second. B is the bandwidth of the channel in Hertz and S/N is the signal to noise ratio.

2. The graph K 3,4 has _______ edges.
(A). 3 edges (B) 4 edges
(C ). 7 edges (D) 12 edges
Ans : D. A bipartite graph is a complete bipartite graph if every vertex in U is connected to every vertex in V. If U has n elements and V has m, then the resulting complete bipartite graph can be denoted by K n,m and the number of edges is given by n*m.
The number of edges = K 3,4 = 3 * 4 = 12

3. The total number of spanning trees that can be drawn using five labeled vertices is:
(A). 125 (B).64
(C ). 36 (D). 16

Ans : A. According to cayley’s formula for counting spanning trees, for a complete graph Kn,
T(Kn)= n n-2 where n is the number of vertices.
T(k5)=5 5-2=5 3= 5 * 5 * 5=125

4. Extremely low power dissipation and low cost per gate can be achieved in
(A) MOS ICS (B) C MOS ICS
(C ) TTL ICS (D) ECL ICS
Ans : B. CMOS ICS

5. An example of a universal building block is :
(A). EX-OR Gate (B). AND Gate
(C ). OR gate (D). NOR Gate
Ans:- D. Universal gates are the ones which can be used for implementing any gate like AND,OR and NOT or any combination of these basic gates. Apart from the NOR gate, NAND gate is also considered as universal gate.

6. An example of a layer that is absent in broadcast networks is :
(A). Physical layer (B). Presentation layer
(C ). Network layer (D). application layer
Ans : C.

7. The ATM cell is :
(A). 48 bytes long (B). 53 bytes long
(C ). 64 bytes long (D). 69 bytes long
Ans: B. An ATM cell always consists of a 5-byte header followed by a 48-byte payload. So the size is 53 bytes long.

8. Four jobs J1,J2,J3, and J4 are waiting to be run. Their expected run times are 9,6,3 and 5 respectively. In order to minimize average response time, the jobs should be run in the order:
(A). J1 J2 J3 J4 (B). J4 J3 J2 J1
(C ) J3 J4 J1 J2 (D) J3 J4 J2 J1
Ans : D

9. Suppose it takes 100ns to access page table and 20 ns to access associative memory. If the average access time is 28ns, the corresponding hit rate is:
(A). 100 percent (B). 90 percent
(C ). 80 percent (D). 70 percent
Ans : B

10. Transmission of N signals , each band limited to Fm Hz by TDM, requires a minimum band-width of
(A).fm (B) 2 fm
(C ) N fm (D) 2N fm
Ans : C. Minimum transmission band-width of TDM channel is given by the following equation.
Bt=NW
Where N is the total number of channels, which are bandlimited to ‘W’ Hz. In the above problem, the number of signals are N, each band limited to Fm Hz and so the minimum band-width is N fm.

11. If a code is ‘t’ error detecting, the minimum hamming distance should be equal to :
(A). t-1 (B). t
(C ). t+1 (D). 2t+1
Ans: C. To guarantee the detection of upto s errors in all cases, the minimum hamming distance in a block code must be
dmin=s+1
So, the minimum hamming distance for a ‘t’ error detecting must be t+1

12. A relation R in {1,2,3,4,5,6} is given by {(1,2),(2,3),(3,4),(4,4),(4,5)}. The relation is :
(A) Reflexive (B). symmetric
(C ). Transitive (D). not reflexive, not symmetric and not transitive
Ans:- D.

13. The dual of the switching function x+yz is:
(A). x+yz (B). x+yz
(C ). x(y+z) (D). x(y+z)
Ans:- D

14. The characteristic equation of D-flip flop is :
(A). Q=1 (B). Q=0
(C ). Q=D (D). Q=D
Ans: D.

15. If four 4 input mulitplexers drive a 4 input multiplexer we get a :
(A). 16 input MUX (B). 8 input MUX
(C ). 4 input MUX (D). 2 input MUX
Ans:- A

16. The throughput of slotted ALOHA is given by:
(A). S=G (B). S=GeG
(C ). S=Ge-G (D). S=eG
Ans: C

17. Congestion control is done by
(A). Network layer (B). Physical layer
(C ). Presentation layer (D). Application layer
Ans:- A. Addressing, internetworking, error handling, packet sequencing are its other jobs.

18. Assertion(A): Twisted pairs are widely used as transmission medium.
Reasoning(R ): Twisted pairs have adequate performance and low cost.
(A). Both (A) and (R ) are true and (R ) is the correct explanation for (A).
(B). Both (A) and (R ) are true but (R ) is not the correct explanation
(C ). (A) is true but (R ) is false
(D). (A) is false but (R ) is true
Ans:- A. Page No .91 of Tanenbaum book, you will find the following statement. “Due to their adequate performance and low cost, twister pairs are widely used and are likely to remain so for years to come”.

19. An example of a non-adaptive routing algorithm is:
(A). Shortest path routing (B). Centralised routing
(C ). Baran’s hot potato algorithm (D). Baran’s backward learning algorithm
Ans:- A. Shortest path routing.

20. IP address in B class is given by:
(A). 125.123.123.2 (B). 191.023.21.54
(C ). 192.128.32.56 (D). 10.14.12.34
Ans:- B

21. N processes are waiting for I/O. A process spends a fraction of its time in I/O wait state. The CPU utilization is given by:
(A). 1-P –N (B). 1 – P N
(C ). P N (D). P -N
Ans:B. According to the probabilistic model, if a process spends a fraction p of its time in I/O wait state, and if there are N processes in memory, then the CPU utilization is given by 1-PN

22. If holes are half as large as processes, the fraction of memory wasted in holes is:
(A) 2 / 3 (B). 1 / 2
(C ). 1 / 3 (D). 1 / 5
Ans : D

23. An example of a non-premptive scheduling algorithm is:
(A). Round robin (B). Priority scheduling
(C ). Shortest job first (D). 2 level scheduling
Ans: C

24. An example of a distributed OS is:
(A). Amoeba (B). UNIX
(C ). MS – DOS (D). MULTICS
Ans: A

25. Which one of the following correctly describes a static variable:
(A). It cannot be initialized.
(B). It is initialized once at the commencement of execution and cannot be changed during run time.
(C ). It retains its value during the life of the program.
(D). None of the above
Ans: C

26. The output of the program code
main()
{
int x = 0;
while ( x < = 10)
for(;;)
if (++x%10==0)
break;
printf(“x=%d”,x);
}
is:
(A). x = 1 (B). compilation error
(C ). x = 20 (D) none of the above
Ans:- C. For the while statement there is a for loop inside. For the for loop, there is one if condition, based on which there is a break statement. Since the value of x initially is 0, the while condition would be true and the for loop would start executing. The if statement condition would be checked, since ++x would become 1 and 1%10 is not equal to 0, break will not be executed. Since for is infinite x value will go on increasing. Once the value of x reaches 9, ++x would become 10 and 10%10==0 and so break would be executed. So control will come out of the innermost loop and would go to the outer loop. Sinc the value of x is 10, and since it is equal to 10, once again the for loop would start its execution. Once the value of x reaches 20, 20%10 will be equal to 0 and again break will be executed and control would go to the outer for loop. When the condition is checked for x<=10,it is false as the value of x is 20 and so it comes out of the while loop and the printf statement gets executed, printing the value of 20. Whew!!!!! 27. A copy constructor is invoked when : (A). a function returns by value (B). an argument is passed by value (C ). A function returns by reference (D). none of the above Ans:- B 28. When a language has the capability to produce new data types, it is said to be : (A). extensible (B). encapsulated (C ). Overloaded (D). none of the above Ans:-A 29. How many constructors can a class have? (A) Zero (B) 1 (C ) 2 (D) any number Ans:- D 30. An entity has: (i) a set of properties (ii) a set of properties and values for all the properties (iii) a set of properties and the values for some set of properties may non-uniquely identify an entity (iv) a set of properties and the values for some set of properties may uniquely identify an entity Which of the above are valid? (A) (i) only (B) (ii) only (C ) (iii) only (D) (iv) only Ans:- D 31. Aggregation is: (A) An abstraction through which relationships are treated as lower level entities (B) An abstraction through which relationships are treated as higher level entities (C) An abstraction through which relationships are not treated at all as entities (D) None of the above Ans:- B 32. Suppose R is a relation schema and F is a set of functional dependencies on R. Further, suppose R1 and R2 forma a decomposition of R. Then the decomposition is a lossless join decomposition of R provided that : (A) R1∩R2 ->R1 is in F+
(B) R1 ∩ R2->R2 is in F+
(C) Both R1 ∩ R2->R1 and R1 ∩ R2->R3 functional dependencies are in F+
(D)At least one from R1∩R2->R1 and R1 ∩ R2->R2 is in F+
Ans:- D.

33. In a heap, every element is ________________ of all the elements in the subtree.
(A) Maximum (B) minimum
(C ) sum (D) product
Ans:- A

34. If (rear == maxsize – 1) rear=0; else rear=rear+1; is required in :
(A) circular queue (B) linear queue (C) stack (D) deque
Ans:- D

35. A high performance switching and multiplexing technology that utilizes fixed length packets to carry different types of traffic is :
(A) ATM (B) ADSL (C) SONET (D) None of the above
Ans:- A

36. A conventional LAN bridge specifies only the functions of OSI:
(A) Layers 1 and 2 (B) layers 1 through 3 (C) all layers (D) none of the above
Ans:- A.

37. An assembly program contains:
(A) Imperative and declarative statements
(B) Imperative statements and assembler directives
(C) Imperative and declarative statements as well as assembler directives
(D) Declarative statements and assembler directives
Ans:- C. Assembly program consists of three types of statements.
1. Imperative
2. Declarative
3. Assembler directives

38. In which addressing mode, the effective address of the operand is generated by adding a constant value to the contents of a register?
(A) Absolute mode (B) immediate mode (C) indirect mode (D) index mode
Ans:- D

39. Which of the following are Assembler directives?
(i) EQU (ii) ORIGIN (iii) START (iv) END
(A) (ii),(iii) and (iv) (B) (i),(iii) and (iv)
(B) (iii) and (iv) (D) (i),(ii),(iii) and (iv)
Ans:- D

40. Which of the following OS treats hardware as a file system?
(A) UNIX (B) DOS (C) Windows NT (D) none of the above
Ans:- A.

41. In which of the following, ready to execute processes must be present in RAM?
(A) Multiprocessing (B) multiprogramming (C) multitasking (D) all of the above

42. If the executing program size is greater than the existing RAM of a computer, it is still possible to execute the program if the OS supports:
(A) Multitasking (B) virtual memory (C) paging system (D) none of the above
Ans: B

43. Software Quality Assurance (SQA) encompasses:
(A) Verification (B) validation (C) both verification and validation (D) none of the above

44. Which level is called as “defined” in capability maturity model?
(A) Level 0 (B) level 3 (C) level 4 (D) level 1
Ans:- B

45. COCOMO model is used for:
(A) Product quality estimation (B). product complexity estimation
(C) product cost estimation (D) all of the above
Ans: C

46. Font sizes are usually expressed in points. One point is:
(A) 0.0069 inch (B) 0.0138 inch
(C) 0.0207 inch (D0 0.0276 inch
Ans:- B. One point is 1/72 of an inch and so we will get the answer 0.0138 inch.

47. Assertion (A): Cellular telephone systems can handle a multitude of users.
Reasoning(R ): Cellular telephone systems permit extensive frequency reuse in a small local area.
(A) Both (A) and (R ) are true and (R ) is the correct explanation for (A)
(B) Both (A) and (R ) are true but (R ) is not the correct explanation
(C) (A) is true but (R ) is false
(D) (A) is false but (R ) is true
Ans:- A.

48. E-Commerce involves:
(A)Electronic Data Interchange (B) Electronic mail
(C) Electronic Bulletin boards (D) All of the above
Ans:- D. E-commerce involves paperless transactions and usage of EDI(Electronic Data Interchange), electronic mail, bulletin boards, fax transmission and electronic fund transfers.

49. An example of a data mining algorithm which uses squared error score function is:
(A) CART algorithm (B) back propagation algorithm (C) a priori algorithm
(D) vector space algorithm
Ans:- B. Back propagation algorithm uses squared error score function. CART algorithm uses cross-validated loss function.

50. (I) Each object in the active directory of windows 2000 has an access control list.
(II) The scheme is a blueprint of all objects in the domain of windows 2000. Which of the following is true?
(A) Only (I) (B) only (II) (C) both (I) and (II) (d) none of the above
Ans:- C

# DECEMBER 2009 PAPER II SOLVED

1. If she is my friend and you are her friend, then we are friends. Given this, the friend relationship in this context is ________________.
(i) Commutative (ii) transitive (iii) implicative (iv) equivalence
(A) (i) and (ii) (B) (iii) (C) (i),(ii),(iii) and (iv) (D) None of these
Ans:- D

2. Circle has ________
(A) No vertices (B) only 1 vertex (C) vertices (D) None of these
Ans :- A

8. The highest noise margin is offered by
(A) BICMOS (B) TTL (C) ECL (D) CMOS
Ans:- B

9. The answer of the operation (10111)2 * (1110)2 in hex equivalence is
(A) 150 (B) 241 (C) 142 (D) 101011110
Ans:- C

10. How many ‘1’ are present in the binary representation of
3 X 512 + 7 X 64 + 5 X 8 + 3
(A) 8 (B) 9 (C) 10 (D) 11
Ans:- B

11. Recursive functions are executed in a
(A) First in first out order (B) Last in first out order
(C ) Parallel fashion (D) Load Balancing
Ans: B

12. What would be the output of the following program, if run from the commandline as “myprog 1 2 3”?
main(int argc,char *argv[])
{
int i;
i=argv[1]+argv[2]+argv[3];
printf(“%d”,i);
}
(A) 123 (B) 6 (C) Error (D) “123”
Ans:- C

13. A ________________ is a special method used to initialize the instance variable of a class.
(A) Member function (B) Destructor (C) Constructor (D) structure
Ans:- C

14. Encapsulation is
(A) Dynamic binding
(B) A mechanism to associate the code and data
(C ) Data abstraction
(D ) Creating new class
Ans:- B

15. Which of the statements are true?
II. Protected members are accessible to the member of a derived class.
III. A derived class inherits constructors and destructors
IV. A friend function can be called like a normal function.
V. Nested class is a derived class.
(A) I,II,III (B) II,III,V (C) III,IV,V (D) I,II,IV
Ans:- D

16. The E-R model is expressed in terms of
I. Entities
II. The relationship among entitites
III. The attributes of the entities.
IV. Functional relationship.
(A) I,II (B) I,II, IV (C) II,II,IV (D) I,II,IV
Ans:- D

17. Specialization is ________________process.
(A) top-down (B) bottom up
(C ) both (A) and (B) (D) none of these
Ans:- A

18. Match the following:
(1) Determinants (a) No attributes
(2) Candidate key (b) Uniquely identified a row
(3) Non-redundancy (c ) A constraint between two attributes
(4) Functional dependency (d) Group of attributes on the left hand side of arrow
of function dependency
(A) 1 – d, 2 – b, 3 – a, 4 – c
(B) 2 – d, 3 – a, 1- b, 4 – c
(C) 4 – a, 3 – b, 2 – c, 1 – d
(D) 3 – a, 4 – b, 1 – c, 2 – d
Ans:- A.

19. A function that has no partial functional dependencies is in _____________ form.
(A) 3 NF (B) 2 NF (C) 4 NF (D) BCNF
Ans:- B

20. Which of the following statement is wrong?
I. 2-phase locking protocol suffer from dead lock.
II. Time stamp protocol suffer from more aborts.
III. A block hole in a DFD is a data store with only inbound flows.
IV. Multivalued dependency among attribute is checked at 3 NF level.
V. An entity-relationship diagram is a tool to represent event model.
(A) I ,II,III (B) II,III,IV (C) III,IV,V (D) II,IV,V
Ans:- A

21. If the number of leaves in a strictly binary tree is an odd number, then what can you say with full conviction about total number of nodes in a tree?
(A) It is an odd number.
(B) It is an even number.
(C ) It cannot be equal to the number of leaves.
(D ) It is always greater than twice the number of leaves.
Ans:- A. Strictly binary tree with N leaves contains 2N-1 nodes. So when the number of leaves is odd number then the total number of nodes in the tree also will be odd if we apply the above formula.

22. The number of edges in a complete graph of n vertices is
(A) n (B) n(n-1)/2 (C ) n(n+1)/2 (D) n2/2
Ans:- B. The complete graph on n vertices has n(n-1)/2 edges.

23. At a hill station, the parking lot is one long drive way snaking up a hill side. Cars drive in and park right behind the car in front of them, one behind another. A car can’t leave until all the cars in front of it have left. Is the parking lot more like
(A) An array (B) A stack (C) A queue (D) A linked list
Ans:- C.

24. With regard to linked list, which of the following statement is false ?
(A) An algorithm to search for an element in a singly linked list requires O(n) operations in the worst case.
(B) An algorithm for deleting the first element in a singly linked list requires o(n) operations in the worst case.
(C ). An algorithm for finding the maximum value in a circular linked list requires o(n) operations.
(D ). An algorithm for deleting the middle node of a circular linked list requires o(n) operations.
Ans:- B

25. A hash function f defined as f(key)=key mod 7, with linear probing used to resolve collisions. Insert the keys 37,38,72,48,98 and 11 into the table indexed from 0 to 6. What will be the location of 11?
(A) 3 (B) 4 (C ) 5 (D) 6
Ans:- C

26. Device on one network can communicate with devices on another network via a
(A) Hub/switch (B) Utility server
( C) File server (D) Gateway
Ans:- D

27. What is the maximum window size in sliding window protocol used in a computer network?
(A) 4 (B) 8 (C ) 15 (D) 16
Ans:- A

28. Which of the following are Data Link Layer standard?
1. Ethernet 2. HSSI 3. Frame Relay
4. 10-Base T 5. Token Ring
(A) 1,2,3 (B) 1,3,5 (C) 1,3,4,5 (D) 1,2,3,4,5
Ans:- C

29. In case of Bus/Tree topology signal balancing issue is overcome by
(A) Modulation (B) Polling
(C ) Segmentation (D) Strong transmitter
Ans:- C

30. Match the following:
(i) Ethernet (a) Deterministic
(ii) Token Ring (b) Utilize the full wire speed
(iii) Cut-through switch (c ) Prevent Looping
(iv) Spanning tree (d) Checking valid address
Codes:
(A) i-d,ii-a,iii-b,iv-c (B) i-a,ii-d,iii-b,iv-c
(C ) i-d,ii-d,iii-c,iv-b (D) i-d,ii-c,iii-b,iv-a
Ans:- A

32. Which of the following grammar is LR(1)?
(A) A->aAb, A->bAb,A->a,A->b
(B) A->aAa,A->aAb,A->c
(C ) A->A+A,A->a
(D)Both (A) and (B)

33. A shift-reduce parser carries out the actions specified within braces immediately after reducing with the corresponding rule of the grammar.
S->xxW[ print “1” ]
S->y [ print “2” ]
W->S2 [ print “3” }, what is the translation of “x x x x y z z”?
(A) 1 1 2 3 1 (B) 1 1 2 3 3 (C) 2 3 1 3 1 (D) 2 3 3 2 1
Ans:- C

34. Context-free Grammar(CFG) can be recognized by
(A) Finite state automata
(B) 2-way linear bounded automata
(C ) push down automata
(D ) Both (B) and (C)
Ans:- D

35. Synthesized attribute can be easily simulated by a
(A) LL grammar (B) Ambiguous grammar
(C ) LR grammar (D) None of the above
Ans:- C

36. In the process management Round-robin method is essentially the pre-emptive version of _______________.
(A) FILO (B) FIFO
(C ) SSF (D) Longest time first
Ans:- B

37. A page fault
(A) is an error specific page
(C ) occur when a page program occur in a page memory.
(D ) page used in the previous page reference.
Ans:- B

38. A semaphore count of negative n means (s=-n) that the queue contains ___n__________ waiting processes.
(A) n + 1 (B) n (C) n – 1 (D) 0
Ans:- B

39. A program is located in the smallest available hole in the memory is ______________
(A) best-fit (B) first-bit (C ) worst-fit (D ) buddy
Ans:- A

40. The unix command used to find out the number of characters in a file is
(A) nc (B) wc (C ) chcnt (D) lc
Ans:- B

41. Software Engineering is a discipline that integrates __________ for the development of computer software.
(A) Process (B) Methods (C ) Tools (D) All
Ans:- D

42. Any error whose cause cannot be identified anywhere within the software system is called _________________.
(A) Internal error (B) External error
(C ) Inherent error (D) Logic error
Ans:- B

43. Recorded software attributes can be used in the following endeavours:
(i) Cost and schedule estimates.
(ii) Software product reliability predictions
(iii )Managing development process
(iv). No where
Codes:
(A) (i) (ii) (iv)
(B) (ii) (iii) (iv)
(C) (i) (ii) (iii)
(D) (i) (ii) (iii) (iv)
Ans :- C

44. Black box testing is done
(A) To show that s/w is operational at its interfaces i.e. input and output.
(B) To examine internal details of code
(C) At client side
(D) None of the above
Ans:- A

45. The name of the transaction file shall be provided by the operator and the file that contains the edited transactions ready for execution shall be called
(A) Batch.exe (B) Trans.exe (C ) Opt.exe (D) Edit.exe
Ans:- C

46. The single stage network is also called
(A) One sided network (B) two sided network (C ) recirculating network
(E) pipeline network
Ans:- C. The single stage network is also called a recirculating network.

47. Analysis of large database to retrieve information is called
(A) OLTP (B) OLAP (C ) OLDP (D) OLPP
Ans:- B
48. Which technology is sometime referred to as wireless cable?
(A) MMDS (B) ATM (C ) LMDS (D) CDMA
Ans:- A. MMDS stands for multipoint multichannel distribution system. MMDS is a broadband wireless technology.

49. Another name of IEEE 802.11 a is ______________
(A) Wi-Max (B) Fast Ethernet (C) Wi-fi (D) 802.11 g
Ans:- C. IEEE 802.11 standards provide the basis for Wi-fi networks.

50. The unlicensed National Information Infrastructure band operates at the ____________frequency
(A) 2.4 GHz (B) 5 GHz (C ) 33 MHz (D) 5 MHz
Ans:- B

1. thanks for ur great help and kindness

1. THANKS ANISH...

2. You have mentioned the answer for 8th question as B.
Answer for 8 is D. I found on wiki that Noise margins for CMOS chips is usually much greater than TTL. http://en.wikipedia.org/wiki/Noise_margin

Please see if this is correct

3. Hi vani,

I appreciate your efforts.im also searching for solutions on google.This blog is very helpful to everyone.Thank you so much.

4. This comment has been removed by the author.

5. Hi Miss

Thank you very much....

Me Habeeb doing MSc in computer science completed BSc with third rank from university of Calicut
Please suggest me some books and guide for UGC NET JRF in computer science
email: habeebp098@gmail.com

6. salam
good work done, i read upkars ugc net/jrf/set according to new pattern book, but found most of the answer keys wrong, so be cautious while preparing for such type of examination, which can change ur life. i suggest dont take any risk while considering keys, only if u know then,
thanks

7. great effort ma'm..i really needed one as i'm preparing UGC NET exam.Truly there is no material support for computer science subject especially for UGC NET Exam on the internet.I'll will be highly obliged if you can give some more material regarding this exam as now this is totally objective pattern from june'2012.

1. Good evening mam. This blog is really useful to us. I need materials for paper 3 mam. Model question paper for paper 3. Thank u mam. Can u send materials . This is my id d.a.thenu@gmail.com

8. HAI VANI-THIS IS BADRI-GREAT WORK-FOLLOWING YOUR BLOG-HELPING ME A LOT IN THE PREPARATION

9. HAI MAM-DEC 2009-PLS CHECK 20TH QUESTION-ANSWER MAY BE A-JUST C

10. mam-i have solved june 2011, dec-2010, and june 2010 to the questions i knw. can v discuss the same

1. yes sir we will discuss it...

2. great to hear from u sir, let us put more solved papers ....what say..

bye..

3. possible to put more solved papers..its very usefull

11. This comment has been removed by the author.

12. This comment has been removed by the author.

13. Hi Mam,
This is Dheeraj, preparing for this June'2012 NET Computer Sc, very useful information you have given through your blogger. Thanks.

14. Great work, madam. Just a doubt - Dec 2008 Q 34 - the answer looks very much like (a) - circular queue. You have listed as deque. Could you confirm?

Thanks.

15. Hi Mam
Is there any Another Solve Paper Like june 2011, june 2010 & others . if Yes ,Then send URL .if u have any Guess Questions for June 2012 send me

Regards:-
Sanjay

16. Hi..this is Gopi this website is very useful and i need few more materials or any other website. if u find any pls revert to gopi.mca11@gmail.com

17. thanks a lot :)

18. Thank u very much... It is very helpful

19. Thanks for sharing such useful. Please Provide some Informations regarding UCG NET Coaching CTET Coaching.

20. thank u mam its really gud ,pls share solved problems for compiler design n TOC

21. Thanks for UGC NET computer science Question papers. Is engineering graduate(computer science) eligible for UGC NET computer science exam?