DECEMBER 2010 PAPER SOLVED QUESTIONS 1 - 10
1. The number of integers between 1 and 250 that are divisible by 2,5 and 7 is
A)  2 (B) 3
C) 5 (D) 8
Ans:- B. There are 3 integers between 1 and 250 that are divisible by 2,5 and 7. They are 70,140 and 210.
2. An undirected graph possess an Eulerian circuit if and only if it is connected and its vertices are
A) All of even degree (B)All of odd degree
C) Of any degree (D)even in number
Ans:- A. According to Euler's theorem 1, if a graph is undirected then it has an eulerian circuit if and only if it is connected and each vertex has an even degree.
***It would be useful to know about the Hamiltonian circuit as well.
3. A partially ordered set is said to be a lattice if every two elements in the set have
A)a unique least upper bound (B)a unique greatest lower bound
C)both (A) and (B) (D)none of the above.
Ans:- C.
4. The minimum number of edges in a connected graph with 'n' vertices is equal to
A)n(n-1) (B)n(n-1)/2
C)n2 (D)n-1
Ans:- D. The formula for counting the minimum number of edges in a connected graph is (n-1).
5. Would be done later.....
6. The decimal number equivalent of (4057.06)8 is :
A) 2095.75 (B)2095.075
C) 2095.937 (D)2095.09375
Ans:- D.
7. Would be done later...
8. An astable multivibrator has
A)one stable state (B)two stable states
C)no stable states (D)none of these
Ans:- C. An astable multivibrator has two states but neither of them are stable.
9.12-bit 2's complement of -73.75 is
A) 01001001.1100 (B)11001001.1100
C) 10110110.0100 (D)10110110.1100
Ans:- B
10. Encoding of data bits 0011 into 7-bit even parity Hamming code is
A)0011110 (B)0101110
C)0010110 (D)0011100
Ans:- A.
The explanation is quite lengthy. If you google the question, you would get a link to the book "Fundamentals of digital circuit" by A.Anand Kumar. The explanation is great there.
11. How many of the following declarations are correct?
int z=7.0;
double void=0.000;
short array[2]={0,1,2};
char c="\n";
(A) None (B)One is correct
(C) Two are correct (D)All four are correct
Ans:-The second declaration is for sure wrong because we cannot have a keyword as a variable name. The last declaration is also wrong because we cannot assign anything within double quotes to a character variable. So we are left with only the first and the array declaration.I think those two would still not give errors in c. So 'C' could be the answer for this question.
Hi Mam,
ReplyDeleteThis is Dheeraj, preparing for June'24th NET exam.
I really got help from your blog,
Thanks.
In the Q11, 3rd option is also not correct because the array size is less than the no. of elements.(Compile time error: Too many initializers)
So the answer is (B).
yes.
Deleteonly 1 error in ques11.
Thank u dheeraj for your info...
ReplyDeleteWhat is the use of ping command
ReplyDeleteIn the question 9.12-bit 2's complement of -73.75 is
ReplyDeleteA) 01001001.1100 (B)11001001.1100
C) 10110110.0100 (D)10110110.1100
the answer is C not B
so
Ans:- B is wrong
binary of 73.55 0 1 0 0 1 0 0 1 . 1 1 0 0
Delete2,s complement is 1 0 1 1 0 1 1 0 . 0 1 0 0
yes, C is the right ans. binary of +73.75 is 01001001.1100 in 12 bit format. doing 2's complement we get C as required ans
Deleteplease explain how?
DeleteQ 5
ReplyDeletetotal lamp=19
last extension connect to 4 lamp
so 19-4=15
rest extension connect to 3 lamp and 1 extension
15/3=5
total 5+1=6
Ans is C
Same type of Q is in Dec 2012 p iii Q 29
ReplyDeleteQ11 Ans will be B,only the 1st stmt is correct .
ReplyDeletein 3rd stmt Array size is 2 but 3 value have assigned,So it will so error
Q.No 11. Ans will be A, None of the Stmt is correct. array[2] is also correct.bcz size is started from 0 to 2..so 3 values are possible only thing is 'array' is a keyword.so we cannot declare as a array name
ReplyDeleteQ.No 11.Ans will be A)
ReplyDeleteplease explain the question no 1. how we can find the ans.?
ReplyDeletetake the LCM of 2 5 7 that is 70 and then multiple of 70 that is 70 140 and 210
ReplyDeletecan any body explain qn no 9 accrding tp me the ans would be 10110111.0100
ReplyDeleteq no 9
ReplyDeleteam getting 10110111.0000 as answer. can anyone help in explaining this